How do you find the equilibrium constant for the reverse reaction of this problem?

Question

How do you find the equilibrium constant for the reverse reaction of this problem?

Given :
Temperature : 1500 degrees Celcius
Equilibrium Constant : 0.1764
Balanced equation: $C O + 3 H_{2} = C H_{4} + H_{2} O$ $CO + 3 H_2 = CH_4 + H_2O$

Need:
Equilibrium Constant for $C H_{4} + H_{2} O = C O + 3 H_{2}$ $CH_4 + H_2O = CO + 3H_2$

1 Answer

Impact of this question

46030 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-19T19:35:02

$K' = 5.670$ $K'=5.670$

Explanation:

The equilibrium constant for the reaction:

$C O + 3 H_{2} ⇌ C H_{4} + H_{2} O$ $CO+3H_2rightleftharpoons CH_4+H_2O$

is written as:

$K = \frac{[C H_{4}] [H_{2} O]}{[C O] {[H_{2}]}_{2}^{3}} = 0.1764$ $K=([CH_4][H_2O])/([CO][H_2]^3)=0.1764$

The equilibrium constant for the opposite reaction:

$C H_{4} + H_{2} O ⇌ C O + 3 H_{2}$ $CH_4+H_2OrightleftharpoonsCO+3H_2$

is written as:

$K' = \frac{[C O] {[H_{2}]}_{2}^{3}}{[C H_{4}] [H_{2} O]} = \frac{1}{K} = \frac{1}{0.1764} = 5.670$ $K'=( [CO][H_2]^3)/([CH_4][H_2O])=1/K=1/(0.1764)=5.670$

Here is a video that explains this topic in details:
Chemical Equilibrium | The Equilibrium Conditions.

Science

Math

Humanities

... and beyond

How do you find the equilibrium constant for the reverse reaction of this problem?

Given :
Temperature : 1500 degrees Celcius
Equilibrium Constant : 0.1764
Balanced equation: $C O + 3 H_{2} = C H_{4} + H_{2} O$ $CO + 3 H_2 = CH_4 + H_2O$

Need:
Equilibrium Constant for $C H_{4} + H_{2} O = C O + 3 H_{2}$ $CH_4 + H_2O = CO + 3H_2$

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the equilibrium constant for the reverse reaction of this problem?

Given : Temperature : 1500 degrees Celcius Equilibrium Constant : 0.1764 Balanced equation: CO+3H2=CH4+H2OCO + 3 H_2 = CH_4 + H_2O Need: Equilibrium Constant for CH4+H2O=CO+3H2CH_4 + H_2O = CO + 3H_2

1 Answer

Explanation:

Related questions

Impact of this question

Given :
Temperature : 1500 degrees Celcius
Equilibrium Constant : 0.1764
Balanced equation: $C O + 3 H_{2} = C H_{4} + H_{2} O$ $CO + 3 H_2 = CH_4 + H_2O$

Need:
Equilibrium Constant for $C H_{4} + H_{2} O = C O + 3 H_{2}$ $CH_4 + H_2O = CO + 3H_2$