How do you find the equation of the circle with center at (4,-6) and passes through point (7,-2)?
1 Answer
Mar 2, 2017
Equation of a circle is
Explanation:
Equation of a circle with center at
Hence equation of a circle with center at
As it passes through
or
Hence, equation of circle is
or
graph{x^2+y^2-8x+12y+27=0 [-8, 16, -12, 0]}