How do you find the equation of a circle in standard form given C(-2,8) and r=4?

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Answer 1 · 2017-02-03T12:07:41

The equation of circle is #(x+2)^2 +(y-8)^2=16#

The equation of circle in standard form is # (x-h^2) + (y-k)^2 =r^2# , where #(h,k)# is co-ordinate of centre and # r# is the radius of circle.

So The equation of circle is # (x - (-2))^2 + (y-8)^2 =4^2 or (x+2)^2 +(y-8)^2=16# [Ans]