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How do you find the derivative of #g(x)=sqrt(5-3x)#?

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Apr 22, 2015

Let h(x) = x^(1/2)# and #k(x) = 5-3x#

so #g(x) = sqrt(5-3x) = h(k(x))#

#(d g(x))/(dx) = (d h(k(x)))/(d k(x))*(d k(x))/(dx)#

#=(1/2)(k(x))^(-1/2)*(-3)#

#= (-3/2)*1 /sqrt(5-3x)#

#= - 3/(2sqrt(5-3x))#

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