How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? Calculus Basic Differentiation Rules Chain Rule 1 Answer Wataru Sep 19, 2014 By Chain Rule and Power Rule, #y'=1/4(x^2+3x+5)^{1/4-1}cdot(x^2+3x+5)'# #=1/4(x^2+3x+5)^{-3/4}(2x+3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? How do you find the derivative of #y= sqrt((x-1)/(x+1))# ? See all questions in Chain Rule Impact of this question 13866 views around the world You can reuse this answer Creative Commons License