How do you find the derivative of #y=6 cos(x^3+3)# ? Calculus Basic Differentiation Rules Chain Rule 1 Answer Calculus V. Jul 24, 2014 This is a composite of the function #x^3+3# and the function #6cos x#, so we will need the Chain Rule together with #(x^3+3)=3x^2# and #(cos x)'=-sin x# (as shown here:derivative of trig functions ). Thus #(6cos(x^3+3))'=-6sin(x^3+3)\times (x^3+3)'=-18x^2 sin(x^3+3)#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? How do you find the derivative of #y= sqrt((x-1)/(x+1))# ? See all questions in Chain Rule Impact of this question 17058 views around the world You can reuse this answer Creative Commons License