How do you find the derivative of y=6 cos(x^3+3) ? Calculus Basic Differentiation Rules Chain Rule 1 Answer Calculus V. Jul 24, 2014 This is a composite of the function x^3+3 and the function 6cos x, so we will need the Chain Rule together with (x^3+3)=3x^2 and (cos x)'=-sin x (as shown here:derivative of trig functions ). Thus (6cos(x^3+3))'=-6sin(x^3+3)\times (x^3+3)'=-18x^2 sin(x^3+3). Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? How do you find the derivative of y= sqrt((x-1)/(x+1)) ? See all questions in Chain Rule Impact of this question 17445 views around the world You can reuse this answer Creative Commons License