How do you find the critical points to graph #y = 3 sin (2x-2)#?

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Answer 1 · 2018-07-01T13:00:43

As below.

Standard form of the sine function is
#y = A sin (Bx - C)+ D#

#y = 3 sin(2x - 2)#

#A = 3, B = 2, C = 2, D = 0#

#Amplitude = |A| = 3#

Period # = (2pi)/|B| = (2pi)/2 = pi#

Phase Shift # = -C / B = -2/2 =-1#, 1 to the LEFT

Vertical Shift #= D = 0#