How do you find the critical points to graph $y= 2 sin (-2x+pi) +1$ ?

Question

2313 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-24T09:55:14

As below

Standard form of sine function is $y = A sin (Bx - C) + D$

Given $y = 2 sin(-2x + pi) + 1$

$A = 2, B = -2, C = -pi, D = 1$

$Amplitude = |A| = 2$

$"Period " = (2pi) / |B| = (2pi) / 2 = pi$

$"Phase Shift " = -C / B = -pi / -2 = pi/2, " " pi/2 " to the RIGHT"$

$"Vertical Shift " = D = 1$

How do you find the critical points to graph y= 2 sin (-2x+pi) +1y= 2 sin (-2x+pi) +1?