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How do you find the antiderivative #f(x)=6/x^5#?

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Jun 8, 2015

Note that #\int x^{n}\ dx=x^{n+1}/(n+1)+C# when #n!=-1# and that #\int af(x)\ dx=a\int f(x)\ dx# for any constant #a#.

Hence #\int 6/(x^5)\ dx=6\int x^{-5}\ dx=6* x^{-4}/(-4)+C=-3/(2x^4)+C#

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