How do you find an equation of the circle having center (4,-3) and radius 5?

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Answer 1 · 2017-11-18T15:29:32

${(x - 4)}^{2} + {(y + 3)}^{2} = 25$ $(x-4)^2+(y+3)^2=25$

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$

Where $h$ $h$ is the x coordinate of the centre, $k$ $k$ is the y coordinate of the centre and $r$ $r$ is the radius.

So from example:

${(x - (4))}^{2} + {(y - (- 3))}^{3} = 5^{2}$ $(x-(4))^2+(y-(-3))^3=5^2$

$:.$

$(x-4)^2+(y+3)^2=25$