How do you find a standard form equation for the line with #A (-1,4)#; Slope: #2/5#?

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Answer 1 · 2017-07-19T20:29:41

#y-2/5x=4frac(2)(5)# which leads to

#2x-5y =-22#

The standard form of a line is expressed in the following form
#Ax+By=C#, where #A,B and C # are integers

To find this form use the formula #(y-y_1)=m(x-x_1)#

substitute in the point and slope (m)

#(y-4)=2/5(x-(-1))" "# or #" "(y-4)=2/5(x+1)#

#y-4=2/5x+2/5#

#y=2/5x+2/5+4#

#y=2/5x+4frac(2)(5)" "# now put into standard form

Multiply by #5# to clear the denominators

#5y-(cancel5xx2)/cancel5x=cancel5xx22/cancel5#

#5y-2x=22#

# rArr 2x-5y = -22#