How do you find a numerical value of one trigonometric function of x given #(1+tanx)/(1+cotx)=2#?

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Answer 1 · 2016-11-12T10:18:42

#x=1.107148718+pin#

#(1+tanx)/(1+cotx) = 2#

#(1+tanx)/(1+1/tanx) = 2#

#(1+tanx)/((tanx+1)/tanx) = 2#

#(1+tanx)*tanx/(tanx+1) = 2#

#cancel(1+tanx)*tanx/cancel(tanx+1) = 2#

#tanx=2#

#x=tan^-1 2#

#x=1.107148718+pin#