How do you find a numerical value of one trigonometric function of x given $\frac{1 + tan x}{1 + cot x} = 2$ $(1+tanx)/(1+cotx)=2$ ?

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Answer 1 · 2016-11-12T10:18:42

$x = 1.107148718 + π n$ $x=1.107148718+pin$

$\frac{1 + tan x}{1 + cot x} = 2$ $(1+tanx)/(1+cotx) = 2$

$\frac{1 + tan x}{1 + \frac{1}{tan x}} = 2$ $(1+tanx)/(1+1/tanx) = 2$

$\frac{1 + tan x}{\frac{tan x + 1}{tan x}} = 2$ $(1+tanx)/((tanx+1)/tanx) = 2$

$(1 + tan x) \cdot \frac{tan x}{tan x + 1} = 2$ $(1+tanx)*tanx/(tanx+1) = 2$

$cancel(1+tanx)*tanx/cancel(tanx+1) = 2$

$tanx=2$

$x=tan^-1 2$

$x=1.107148718+pin$

How do you find a numerical value of one trigonometric function of x given (1+tanx)/(1+cotx)=21+tanx1+cotx=2(1+tanx)/(1+cotx)=2?