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How do you express the complex number in trigonometric form: 3?

1 Answer

Shwetank Mauria

Jun 27, 2016

#3# is written as #3cos0+isin0# or #3e^(i0)#

Explanation:

A number #a+ib# is written as #rcostheta+irsintheta# or #re^(itheta)# in polar form,

where #r=sqrt(a^2+b^2)# and #tantheta=b/a#

As #3=3+i0#, #r=sqrt(3^2+0^)=sqrt9=3#

and as #tantheta=0/3=0#, #theta=0#

Hence #3# is written as #3cos0+isin0# or #3e^(i0)#

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