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How do you express the complex number in trigonometric form: #-2#?

1 Answer

Apr 29, 2016

#2cos pi +i sin pi#.

Explanation:

A real number has the argument equal to zero if positive or #pi# if negative:

So, it is #2cos pi +i sin pi#.

#sin pi=0# so number is real;
#cos pi=-1# so the number is negative.

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