How do you express the complex number in standard form: #8(cos 30 +i sin 30)#? Precalculus Complex Numbers in Trigonometric Form Trigonometric Form of Complex Numbers 1 Answer Shwetank Mauria Sep 1, 2016 #8(cos30^o+isin30^o)=4sqrt3+4i# Explanation: #8(cos30^o+isin30^o)# = #8(sqrt3/2+i×1/2)# = #4sqrt3+4i# Answer link Related questions How do I find the trigonometric form of the complex number #-1-isqrt3#? How do I find the trigonometric form of the complex number #3i#? How do I find the trigonometric form of the complex number #3-3sqrt3 i#? How do I find the trigonometric form of the complex number #sqrt3 -i#? How do I find the trigonometric form of the complex number #3-4i#? How do I convert the polar coordinates #3(cos 210^circ +i\ sin 210^circ)# into rectangular form? What is the modulus of the complex number #z=3+3i#? What is DeMoivre's theorem? How do you find a trigonometric form of a complex number? Why do you need to find the trigonometric form of a complex number? See all questions in Trigonometric Form of Complex Numbers Impact of this question 3142 views around the world You can reuse this answer Creative Commons License