How do you differentiate $y = 3 x cos (\frac{x}{3}) - sin (\frac{x}{3})$ $y = 3x cos (x/3) - sin (x/3)$ ?

Question

4934 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-13T01:36:56

the answer
$y'=[8cos(x/3)]/3-xsin(x/3)$

show below

$y = 3x cos (x/3) - sin (x/3)$

$y'=3[x*-1/3sin(x/3)+cos(x/3)*1]-1/3*cos(x/3)$

$y'=-x*sin(x/3)+3cos(x/3)-1/3*cos(x/3)$

$y'=[8cos(x/3)]/3-xsin(x/3)$

How do you differentiate y = 3x cos (x/3) - sin (x/3)y=3xcos(x3)−sin(x3) y = 3x cos (x/3) - sin (x/3)?