How do you differentiate $y = sin^2(x) + sinx$ ?

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Answer 1 · 2016-09-04T00:22:58

$y' = sin2x + cosx$

$y = sinx(sinx + 1)$

$y' = cosx(sinx + 1) + sinx(cosx)$

$y' = cosxsinx + cosx + sinxcosx$

$y' = 2sinxcosx + cosx$

$y' = sin2x + cosx$

Hopefully this helps!

How do you differentiate y = sin^2(x) + sinxy = sin^2(x) + sinx?