How do you differentiate $cos(x^2)$ ?

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Answer 1 · 2016-07-02T12:13:01

$- 2x sin x^2$

so $y = cos u implies dy/(du) = -sin u$

$u = x^2 implies (du)/dx = 2x$

Chain rule $dy/dx = dy/(du)* (du)/dx$

$= - sin u * 2x = - 2x sin x^2$

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