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How do you convert the complex the number into polar representation: #2 sqrt(3) + 2i#?

1 Answer

Jul 15, 2016

#= 4 e^( i pi/6)#

Explanation:

#2 sqrt(3) + 2i#

#= 4 (sqrt(3)/2 + i/2)#

#= 4 (cos (pi/6) + i sin (pi/6))#

#= 4 e^( i pi/6)#

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