How do you convert the complex the number into polar representation: #2 sqrt(3) + 2i#? Precalculus Complex Numbers in Trigonometric Form Trigonometric Form of Complex Numbers 1 Answer Eddie Jul 15, 2016 #= 4 e^( i pi/6)# Explanation: #2 sqrt(3) + 2i# #= 4 (sqrt(3)/2 + i/2)# #= 4 (cos (pi/6) + i sin (pi/6))# #= 4 e^( i pi/6)# Answer link Related questions How do I find the trigonometric form of the complex number #-1-isqrt3#? How do I find the trigonometric form of the complex number #3i#? How do I find the trigonometric form of the complex number #3-3sqrt3 i#? How do I find the trigonometric form of the complex number #sqrt3 -i#? How do I find the trigonometric form of the complex number #3-4i#? How do I convert the polar coordinates #3(cos 210^circ +i\ sin 210^circ)# into rectangular form? What is the modulus of the complex number #z=3+3i#? What is DeMoivre's theorem? How do you find a trigonometric form of a complex number? Why do you need to find the trigonometric form of a complex number? See all questions in Trigonometric Form of Complex Numbers Impact of this question 7359 views around the world You can reuse this answer Creative Commons License