How do you convert #(2,2)# into polar forms?

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How do you convert #(2,2)# into polar forms?

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Answer 1 · 2016-03-18T14:51:35

#(2sqrt2,pi/4)#

Explanation:

#x=rcostheta=>2=rcostheta#
#y=rsintheta=>2=rsintheta#
combining these two
#tantheta=2/2=1=>theta =arctan1=pi/4#
#r=sqrt(x^2+y^2)=sqrt(2^2+2^2)=2sqrt2#
hence polar coordinate
#(2sqrt2,pi/4)#

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How do you convert #(2,2)# into polar forms?

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