How do you complete the square to solve $-3x^2-18x-25= 0$ ?

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Answer 1 · 2015-06-07T23:56:38

$f(x) = -3(x^2 + 6x + 9) + 27 - 25 = 0$

$(x + 3)^2 = (-2)/(-3) = 2/3$ --> $(x + 3) = +- sqrt2/sqrt3 = +-sqrt6/3$

$x = - 3 +-sqrt6/3$

How do you complete the square to solve -3x^2-18x-25= 0-3x^2-18x-25= 0?