How do you complete the square for x^2+8x?
1 Answer
May 15, 2018
Explanation:
"since the coefficient of the "x^2" term is 1"
"add "(1/2"coefficient of the x-term")^2" to"
x^2+8x
rArrx^2+8xcolor(red)(+4)^2=x^2+8x+16=(x+4)^2
