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How do you complete the square for $x^{2} - 8 x$ $x^2 - 8x$ ?

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May 23, 2015

$x^{2} - 8 x + 16$ $x^2 - 8x + 16$

${(x - 4)}^{2} = x^{2} - 8 x + 16$ $(x - 4)^2 = x^2 - 8x + 16$

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