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How do you change #(2)-(2isqrt3)# into polar coordinates?

1 Answer

Vinícius Ferraz

Sep 19, 2015

#4 (cos t + i sin t)#

Explanation:

#2 = r cos t#

#-2 sqrt 3 = r sin t#

#frac {- 2 sqrt 3}{2} = tan t = - sqrt 3#

#r^2 = 2^2 + (-2 sqrt 3)^2 = 4 + 4 * 3 = 16 \Rightarrow r = 4#

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