Between -2pi and 2pi, the graph of the equation y = sin x is symmetric with respect to what?

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Between -2pi and 2pi, the graph of the equation y = sin x is symmetric with respect to what?

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Answer 1 · 2015-10-20T11:47:00

Not only in $[- 2 π, 2 π]$ $[-2pi, 2pi]$ , but over the whole real set, we have that $sin (- x) = - sin (x)$ $sin(-x)=-sin(x)$ . This means that, if you know the value of the sine in a point $x$ $x$ , the opposite point with respect to the $y$ $y$ -axis $- x$ $-x$ will have an opposite value with respect to the $x$ $x$ axis, $- sin (x)$ $-sin(x)$ .

Combining a symmetry with respect to $y$ $y$ -axis and then $x$ $x$ -axis, you get a syimmetry with respect to the origin.

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Between -2pi and 2pi, the graph of the equation y = sin x is symmetric with respect to what?

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