An object is at rest at $(9 ,7 ,3 )$ and constantly accelerates at a rate of $1/4 m/s^2$ as it moves to point B. If point B is at $(6 ,8 ,2 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2016-04-04T20:57:36

$t=25,53 s$

$"let's find distance between (9,7,3) and (6,8,2)"$

$Delta s=sqrt((6-9)^2+(8-7)^2+(2-3)^2)$
$Delta s=sqrt((-3)^2+1^2+(-1)^2)$

$Delta s=sqrt(9+1+1)" "Delta s=sqrt11" m"$

$"distance equation for an object starting from rest:"$

$Delta s=1/2*a t^2$

$a:"acceleration"$
$t:"time"$

$sqrt11=1/2*1/4*t^2$
$t^2=8 sqrt11$

$t^2=sqrt (64*11)$

$t^2=sqrt 704$

$t=25,53 s$

An object is at rest at (9 ,7 ,3 )(9 ,7 ,3 ) and constantly accelerates at a rate of 1/4 m/s^21/4 m/s^2 as it moves to point B. If point B is at (6 ,8 ,2 )(6 ,8 ,2 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.