An object is at rest at $(8 ,1 ,5 )$ and constantly accelerates at a rate of $7/4 m/s^2$ as it moves to point B. If point B is at $(6 ,5 ,2 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2016-04-05T15:30:16

$t=2,48" s"$

$"first; let's find distance between the point of(8,1,5) and (6,5,2)"$

$s=sqrt((6-8)^2+(5-1)^2+(2-5)^2)$

$s=sqrt((-2)^2+4^2+(-3)^2)=sqrt(4+16+9)=sqrt(29)" m"$

$"now ; let's use the equation of "s=1/2*a t^2$

$sqrt29=1/2*7/4* t^2$

$t^2=(8*sqrt29)/7$

$t^2=(8*5,39)/7$

$t=2,48" s"$

An object is at rest at (8 ,1 ,5 )(8 ,1 ,5 ) and constantly accelerates at a rate of 7/4 m/s^27/4 m/s^2 as it moves to point B. If point B is at (6 ,5 ,2 )(6 ,5 ,2 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.