An object is at rest at $(6 ,5 ,9 )$ and constantly accelerates at a rate of $4/3 m/s^2$ as it moves to point B. If point B is at $(3 ,1 ,4 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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An object is at rest at $(6 ,5 ,9 )$ and constantly accelerates at a rate of $4/3 m/s^2$ as it moves to point B. If point B is at $(3 ,1 ,4 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2016-03-19T16:15:23

$~~3.25s$

Explanation:

Here displacement = linear distance between the given points
so displacement $s=sqrt((6-3)^2+(5-1)^2+(9-4)^2)=sqrt50m=5sqrt2m$
Initial velocity $u=0$
Acceleration $a=4/3ms^-2$
time taken t=?

So $s=ut+1/2at^2$
$5sqrt2=0*t+1/2*4/3t^2$
$t^2=3/2*5sqrt2~~10.6$
$t ~~sqrt10.6~~3.25s$

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An object is at rest at $(6 ,5 ,9 )$ and constantly accelerates at a rate of $4/3 m/s^2$ as it moves to point B. If point B is at $(3 ,1 ,4 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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1 Answer

Explanation:

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An object is at rest at $(6 ,5 ,9 )$ and constantly accelerates at a rate of $4/3 m/s^2$ as it moves to point B. If point B is at $(3 ,1 ,4 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.