An object is at rest at $(3, 8, 8)$ $(3 ,8 ,8 )$ and constantly accelerates at a rate of $\frac{7}{5} \frac{m}{s^{2}}$ $7/5 m/s^2$ as it moves to point B. If point B is at $(2, 9, 5)$ $(2 ,9 ,5 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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An object is at rest at $(3, 8, 8)$ $(3 ,8 ,8 )$ and constantly accelerates at a rate of $\frac{7}{5} \frac{m}{s^{2}}$ $7/5 m/s^2$ as it moves to point B. If point B is at $(2, 9, 5)$ $(2 ,9 ,5 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2016-05-01T13:14:36

9.287m/s

Explanation:

First, we need to find the displacement of the object
s= $\sqrt{{(2 - 3)}^{2} + {(9 - 8)}^{2} + {(5 - 8)}^{2}}$ $sqrt((2-3)^2+(9-8)^2+(5-8)^2$
$= \sqrt{11}$ $=sqrt11$
the velocity
$v = \sqrt{2 a s}$ $v=sqrt(2as)$
$v = \sqrt{2 \cdot \frac{7}{5} \cdot \sqrt{11}} = 9.287 \frac{m}{s}$ $v=sqrt(2*7/5*sqrt11)=9.287m/s$

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An object is at rest at $(3, 8, 8)$ $(3 ,8 ,8 )$ and constantly accelerates at a rate of $\frac{7}{5} \frac{m}{s^{2}}$ $7/5 m/s^2$ as it moves to point B. If point B is at $(2, 9, 5)$ $(2 ,9 ,5 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

1 Answer

Explanation:

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1 Answer

Explanation:

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An object is at rest at $(3, 8, 8)$ $(3 ,8 ,8 )$ and constantly accelerates at a rate of $\frac{7}{5} \frac{m}{s^{2}}$ $7/5 m/s^2$ as it moves to point B. If point B is at $(2, 9, 5)$ $(2 ,9 ,5 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.