An object is at rest at $(2 ,9 ,5 )$ and constantly accelerates at a rate of $7/6 m/s$ as it moves to point B. If point B is at $(6 ,2 ,7 )$ , how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2017-07-24T16:08:02

The time is $=3.77s$

The distance is

$s=sqrt((6-2)^2+(2-9)^2+(7-5)^2)$

$=sqrt(16+49+4)$

$=sqrt69$

$a=7/6ms^-2$

The initial velocity is

$u=0ms^-1$

We apply the equation of motion

$s=ut+1/2at^2$

$t^2=(2s)/a$

$=(2*sqrt69)/(7/6)$

$=14.24$

So,

$t=sqrt14.24=3.77s$

An object is at rest at (2 ,9 ,5 )(2 ,9 ,5 ) and constantly accelerates at a rate of 7/6 m/s7/6 m/s as it moves to point B. If point B is at (6 ,2 ,7 )(6 ,2 ,7 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.