A mixture of 2.50mol H2, 1.5 mol CS2, 1.5 mol CH4 and 2mol H2S is placed in a 5.0L reaction vessel. When equilibrium is achieved, the concentration of CH4 has become 0.25M. Whay are the number of moles of CS2 at equilibrium?
A mixture of 2.50mol H2, 1.5 mol CS2, 1.5 mol CH4 and 2mol H2S is placed in a 5.0L reaction vessel. When equilibrium is achieved, the concentration of CH4 has become 0.25M. Whay are the number of moles of CS2 at equilibrium?
A mixture of 2.50mol H2, 1.5 mol CS2, 1.5 mol CH4 and 2mol H2S is placed in a 5.0L reaction vessel. When equilibrium is achieved, the concentration of CH4 has become 0.25M. Whay are the number of moles of CS2 at equilibrium?
1 Answer
The possible reaction occurring in this case is represented by the following equation
The given volume of the reaction mixture is
The initial no. of moles of
At equilibrium the concentration of
So at equilibrium the no. of moles of
So the Change in no. of moles of
Hence the Change in no. of moles of
And at equilibrium the no. of moles of
Using stoichiometric ratio in equation (1) the change in other components can be calculated
Associated ICE table shows the no. of moles of different components presents in the reaction mixture at equilibrium