A circle has a center that falls on the line #y = 5/3x +1 # and passes through #(5 ,2 )# and #(3 ,2 )#. What is the equation of the circle?
1 Answer
Explanation:
Let the given points be
Let us observe that the y-co-ordinates of A & B are same, hence,
We know that the centre of a circle lies on the perpendicular bisector (p.b.) of a chord. Chord
By what is given, centre is also on the line
Solving
So, we get the centre
Next goal is to find radius r of the reqd. cicle. We note that
We use
Hence, the reqd. eqn.of the circle is