A circle has a center that falls on the line y = 3/8x +5 and passes through ( 7 ,3 ) and (5 ,1 ). What is the equation of the circle?

1 Answer
Oct 5, 2016

"equation of circle is :"
(x-2.18)^2+(y-5.82)^2=31.16

Explanation:

"step-1 : draw the line "y=3/8 x+5

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"step-2 : locate "P_1 " and "P_2

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"step -3 : draw a line segment between " P_1 and " P_2

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"step-4 : find the middle point of line segment"

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P_x=(7+5)/2=6
P_y=(3+1)/2=2

P=(6,2)

"step-5 : draw a line perpendicular to line segment and passing through P"

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"the red line's slope : "m_("red")
"segment's slope : "m_("segment")

m_("segment")*m_("red")=-1

1*m_("red")=-1

m_("red")=-1

y-2=-1(x-6)

y-2=-x+6

color(red)(y+x=8)" the red line equation"

"step-6 : now find the coordinate of center of circle (O)"

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"use the two equation :"

y=3/8 x+5

x+y=8

x+3/8 x+5=8

(11x)/8=8-5

11x=24

x=24/11=2.18

2.18+y=8

y=8-2.18=5.82

O=(2.18,5.82)

"step-7 : find distance between O and " P_1" (r)"

r^2=6-2.18)^2+(2-5.82)^2)

r^2=10.24+14.59=31.16

"step-8 : write equation"

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(x-a)^2+(y-b)^2=r^2

(a,b)" center coordinates"

(x-2.18)^2+(y-5.82)^2=31.16