# A body start from rest and with a uniform acceleration of 10m/s^2 for 5 second. during the next 10 second its moves with uniform velocity. the total distance travelled by the body its?

Jul 18, 2018

The total distance travelled is $= 625 m$

#### Explanation:

The initial velocity is $u = 0 m {s}^{-} 1$

The acceleration is $a = 10 m {s}^{-} 2$

The time is $t = 5 s$

Apply the equation of motion

$v = u + a t$

The velocity is

$v = 0 + 10 \cdot 5 = 50 m {s}^{-} 1$

The distance travelled in the first $5 s$ is

$s = u t + \frac{1}{2} a {t}^{2}$

$= 0 \cdot 5 + \frac{1}{2} \cdot 10 \cdot {5}^{2} = 125 m$

The distance travelled in the following $10 s$ is

${s}_{1} = v {t}_{1} = 50 \cdot 10 = 500 m$

The total distance travelled is

$d = s + {s}_{1} = 125 + 500 = 625 m$