A body start from rest and with a uniform acceleration of 10m/s^2 for 5 second. during the next 10 second its moves with uniform velocity. the total distance travelled by the body its?

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Answer 1 · 2018-07-18T08:39:45

The total distance travelled is $=625m$

The initial velocity is $u=0ms^-1$

The acceleration is $a=10ms^-2$

The time is $t=5s$

Apply the equation of motion

$v=u+at$

The velocity is

$v=0+10*5=50ms^-1$

The distance travelled in the first $5s$ is

$s=ut+1/2at^2$

$=0*5+1/2*10*5^2=125m$

The distance travelled in the following $10s$ is

$s_1=vt_1=50*10=500m$

The total distance travelled is

$d=s+s_1=125+500=625m$