Question #c7477

Question

Question #c7477

1 Answer

Impact of this question

1580 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-13T00:15:56

$2 x^{4} + 16 x^{3} + 35 x^{2} + 10 x - 21$ $2x^4+16x^3+35x^2+10x-21$

Explanation:

In problems like these, we have to multiply everything in the first set of parentheses by everything in the second parenthesis.

$x^{2} + 6 x + 7$ $color(blue)(x^2)+color(red)(6x)+color(orange)(7)$

$x^{2} (2 x^{2} + 4 x - 3) + 6 x (2 x^{2} + 4 x - 3) + 7 (2 x^{2} + 4 x - 3)$ $color(blue)(x^2)(2x^2+4x-3)+color(red)(6x)(2x^2+4x-3)+color(orange)(7)(2x^2+4x-3)$

Distributing the $x^{2}$ $color(blue)(x^2)$ :
$2 x^{4} + 4 x^{3} - 3 x^{2}$ $2x^4+4x^3-3x^2$

Distributing the $6 x$ $color(red)(6x)$ :
$12 x^{3} + 24 x^{2} - 18 x$ $12x^3+24x^2-18x$

Distributing the $7$ $color(orange)(7)$ :
$14 x^{2} + 28 x - 21$ $14x^2+28x-21$

Putting it all together:
$2 x^{4} + 4 x^{3} - 3 x^{2} + 12 x^{3} + 24 x^{2} - 18 x + 14 x^{2} + 28 x - 21$ $2x^4+4x^3-3x^2+12x^3+24x^2-18x+14x^2+28x-21$

Combining like terms:

$2 x^{4} + 16 x^{3} + 35 x^{2} + 10 x - 21$ $2x^4+16x^3+35x^2+10x-21$

Science

Math

Humanities

... and beyond

Question #c7477

1 Answer

Explanation:

Related questions

Impact of this question