What are the molecular, ionic, and net ionic equations for the reaction of acetic acid #"HC"_2"H"_3"O"_2# with potassium hydroxide?

1 Answer
Ernest Z.
Jun 21, 2017

Here's what I get.

Explanation:

Molecular equation

#"HC"_2"H"_3"O"_2"(aq)" + "KOH(aq)" → "KC"_2"H"_3"O"_2("aq)" + "H"_2"O(l)"#

Ionic equation

#"HC"_2"H"_3"O"_2"(aq)" + "K"^"+""(aq)" + "OH"^"-""(aq)" → "K"^"+""(aq)" + "C"_2"H"_3"O"_2^"-"("aq)" + "H"_2"O(l)"#

Net ionic equation

Here, we cancel the ions that appear on each side of the equation.

#"HC"_2"H"_3"O"_2"(aq)" + color(red)(cancel(color(black)("K"^"+""(aq)"))) + "OH"^"-""(aq)" → color(red)(cancel(color(black)("K"^"+""(aq)"))) + "C"_2"H"_3"O"_2^"-"("aq)" + "H"_2"O(l)"#

This gives the net ionic equation

#"HC"_2"H"_3"O"_2"(aq)" + "OH"^"-""(aq)" → "C"_2"H"_3"O"_2^"-"("aq)" + "H"_2"O(l)"#

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