Find the equation of a circle, which passes through origin and has #x#-intercept as #3# and #y#-intercept as #4#? What would have been the equation, if intercepts are reversed?
1 Answer
Equation of circle is
Explanation:
It is assumed that intercept on
Let the equation of circle be
As circle passes through
as it passes through
as it also passes through
Equation of circle is
graph{(x^2+y^2-3x-4y)(x^2+y^2-0.01)((x-3)^2+y^2-0.01)(x^2+(y-4)^2-0.01)=0 [-3.77, 6.23, -0.6, 4.4]}
Had the
graph{(x^2+y^2-4x-3y)(x^2+y^2-0.01)((x-4)^2+y^2-0.01)(x^2+(y-3)^2-0.01)=0 [-3.667, 6.33, -0.84, 4.16]}