What is the general formula for substituted aromatic compounds, and substituted arenes in particular?

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What is the general formula for substituted aromatic compounds, and substituted arenes in particular?

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Answer 1 · 2017-07-24T06:22:24

I am not sure what you want...... $C_{6} H_{5} X$ $C_6H_5X$ ?

Explanation:

And of course, $C_{6} H_{5} X$ $C_6H_5X$ specifies four degrees of unsaturation: 3 formal double bonds, and a ring. The $X$ $X$ group (commonly used for halogens) could be any functional group.

Answer 2 · 2017-07-28T20:26:29

I can think of general formulas for two homologous series of aromatic compounds.

Explanation:

In organic chemistry, a homologous series is a group of compounds with the same general formula, usually obtained by varying by the number of carbon atoms.

Based on the number of ${CH}_{2}$ $"CH"_2$ groups

If we start with benzene and add ${CH}_{2}$ $"CH"_2$ groups, we get the series

$C_{6} H_{6}, C_{7} H_{8}, C_{8} H_{10}, C_{9} H_{12}, \dots$ $"C"_6"H"_6, "C"_7"H"_8,"C"_8"H"_10, "C"_9"H"_12, …$

It is common to start the general formula for a homologous series with $n = 1$ $n = 1$ .

This gives us the general formula

$C_{n+ 5} H_{2n + 4}, n = 1, 2, 3, \dots$ $"C"_text(n+ 5)"H"_text(2n + 4), n = 1, 2, 3, …$

Based on the Hückel $4 n + 2$ $4n + 2$ rule

This gives us the series of annulenes:

$C_{6} H_{6}, C_{10} H_{10}, C_{14} H_{14}, C_{18} H_{18}, \dots$ $"C"_6"H"_6, "C"_10"H"_10, "C"_14"H"_14, "C"_18"H"_18, …$

If we start the series with $n = 1$ $n = 1$ , we get the general formula for another aromatic series:

$C_{4n+2} H_{4n+2}, n = 1, 2, 3, \dots$ $"C"_text(4n+2)"H"_text(4n+2), n = 1, 2, 3, …$

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What is the general formula for substituted aromatic compounds, and substituted arenes in particular?

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