Question #3e169

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Answer 1 · 2017-07-10T04:27:12

$a_x = 1.23$ $"m/s"^2$

I'll assume he started from rest, and the acceleration is constant.

We can solve this problem using the kinematics equation

$v_x = v_(0x) + a_xt$

where

He starts with an initial velocity of $0$ (assuming he started from a state of rest), so plugging in known values, we have

$11.1$ $"m/s"$ $= 0 + a_x"("9$ $"s)"$

$a_x = color(red)(1.23$ $color(red)("m/s"^2$

His (assumed to be constant) acceleration is thus $color(red)(1.23$ $sfcolor(red)("meters per second per second"$ .