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Answer 1 · 2017-12-15T01:10:43

The acceleration of the truck is $-6.0 m/s^2$

The 72 m/s is the initial speed, while zero is the final speed. Therefore, the change in speed is $v_f-v_i=-72 m/s$

The acceleration is the rate at which the speed changes each second.

$a=(Deltav)/(Deltat)$

Because this happens in 12 seconds, we can write

$a= (-72)/(12) = -6.0 m/s^2$

Note the units on acceleration $m/s^2$ is read as "meters per second each second"