Question #c7911

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Answer 1 · 2018-01-21T09:57:51

The centripetal acceleration is $= 25 m s^{- 2}$ $=25ms^-2$ and the tangential acceleration is $= 0 m s^{- 2}$ $=0ms^-2$

The speed of the car is $v = 100 m s^{- 1}$ $v=100ms^-1$

The radius of the track is $r = 400 m$ $r=400m$

The angular velocity is $ω = \frac{v}{r} = \frac{100}{400} = 0.25 r a d s^{- 1}$ $omega=v/r=100/400=0.25rads^-1$

The angular acceleration is $α = 0 r a d s^{- 2}$ $alpha=0rads^-2$

The tangential acceleration is $a_{T} = α r = 0 \cdot 400 = 0 m s^{- 2}$ $a_T=alphar=0*400=0ms^-2$

The centripetal acceleration is $a_{C} = \frac{v^{2}}{r} = \frac{100^{2}}{400} = 25 m s^{- 2}$ $a_C=v^2/r=100^2/400=25ms^-2$