(sinx-sinxcosx)/(sinx+sinxtanx)=(1-cosx)/(1+tanx)?

1 Answer
MathFact-orials.blogspot.com
Feb 23, 2017

Factor out sinx in the numerator and denominator of the left side fraction. See below for details:

Explanation:

We have:

(sinx-sinxcosx)/(sinx+sinxtanx)=(1-cosx)/(1+tanx)

I'm first going to factor out sinx in the numerator and denominator on the left side:

(sinx(1-cosx))/(sinx(1+tanx))=(1-cosx)/(1+tanx)

which I can write as:

(sinx/sinx)(1-cosx)/(1+tanx)=(1-cosx)/(1+tanx)

(1)(1-cosx)/(1+tanx)=(1-cosx)/(1+tanx)

(1-cosx)/(1+tanx)=(1-cosx)/(1+tanx)color(white)(000)color(green)sqrt

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