Question #348ea

Question

1239 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-02T22:31:00

see below

Use the Reciprocal Property

#cot v=1/tanv or tan v=1/cotv#

Left Hand Side:

#(1+tan v)/(1-tan v) =( 1+1/cot v)/(1-1/cot v)#

#=(cot v/cotv +1/cot v)/(cot v/cot v-1/cot v)#

#=((cotv+1)/cotv)/((cotv-1)/cotv)#

#=(cotv+1)/cotv * cot v/(cot v-1)#

#=(cotv+1)/cancelcotv * cancelcot v/(cot v-1)#

#=(cot v+1)/(cot v-1)#

#:.=# Right Hand Side