Question #9a883

1 Answer
Feb 10, 2017

This proof actually doesn't require more than a couple steps.

Explanation:

secx+cscx=1/cosx+1/sinx

1/sinx+1/cosx=(sinx+cosx)/(sinxcosx)

secxcscx=1/(sinxcosx)

(secx+cscx)/(secxcscx)=((sinx+cosx)/(sinxcosx))/(1/(sinxcosx))

((sinx+cosx)/(sinxcosx))/(1/(sinxcosx))=((sinx+cosx)/(sinxcosx))*sinxcosx=sinxcosx