Question #7cb8c

Question

2719 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-31T02:40:11

see explanation

#sqrt((1+cos theta)/(1-cos theta)) #

multiply with #sqrt (1+cos theta)#

#sqrt((1+cos theta)/(1-cos theta))*sqrt((1+cos theta)/(1+cos theta)) #

#sqrt(((1+cos theta)/(1-cos theta))*((1+cos theta)/(1+cos theta)) #

#= sqrt((1+cos theta)^2/((1-cos^2 theta)) #

#= sqrt((1+cos theta)^2/sin^2 theta) = (1+cos theta)/sin theta#

#= 1/sin theta +cos theta/sin theta#

#=cosec theta + cot theta#