The first step is to multiply the #1/2# term through the #(x-6)# term.
#1/2x-1/2(6)+1/4(x-12) = 2 - x#
Because one half of six is three, we can rewrite it as
#1/2x-3+1/4(x-12)=2-x#
Next, multiply the #1/4# term through the #(x-12)# term.
#1/2x - 3 + 1/4x-1/4(12)=2-x#
Because one quarter of 12 is 3, we can rewrite it as
#1/2x - 3 + 1/4x-3=2-x#
You can combine the #1/2x# and the #1/4x#. Because
#1/2+1/4=2/4 + 1/4=3/4#, we can rewrite our equation as
#3/4x - 3 -3=2-x#
Because negative 3 minus 3 is negative six, we can rewrite
#3/4x-6=2-x#
Add #6# to both sides
#3/4x=8-x#
Add #x# to both sides
#3/4x+x=8#
Because #x# is really just #1xxx#, we can rewrite as
#3/4x+1xxx=8#
#3/4x+4/4x=8#
#7/4x=8#
Multiply both sides by #4#
#7x=32#
Divide both sides by 7
#x=32/7#
