Question #3ea95

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Question #3ea95

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Answer 1 · 2017-01-01T02:37:03

$L H S = {(2 a sin y cos y)}^{2} + a^{2} {({cos}^{2} y - {sin}^{2} y)}^{2}$ $LHS=(2a sin y cos y)^2 + a^2(cos^2 y-sin^2 y)^2$
$= {(a sin 2 y)}^{2} + a^{2} {(cos 2 y)}^{2}$ $=(a sin2 y)^2 + a^2(cos2 y)^2$
$= a^{2} {sin}^{2} 2 y + a^{2} {cos}^{2} 2 y$ $=a^2 sin^2 2 y + a^2cos^2 2 y$
$= a^{2} ({sin}^{2} 2 y + {cos}^{2} 2 y) = a^{2} \times 1 = a^{2} = R H S$ $=a^2 (sin^2 2 y + cos^2 2 y)=a^2xx1=a^2=RHS$
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Question #3ea95

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