Question #5df8b

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Answer 1 · 2016-12-21T15:06:08

GIVEN

# tan(A+B)/tan(A-B) = lamda#

# =>(sin(A+B)cos(A-B))/(sin(A-B)cos(A+B)) = lamda#

By dividendo and componendo

# =>((sin(A+B)cos(A-B))-(sin(A-B)cos(A+B)))/((sin(A+B)cos(A-B))+(sin(A-B)cos(A+B))) = (lamda-1)/(lambda+1)#

#=>(sin(A+B-A+B))/(sin(A+B+A-B))=(lambda-1)/(lambda+1)#

#=>(sin(2B))/(sin(2A))=(lambda-1)/(lambda+1)#

Proved