Question #6c534

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Answer 1 · 2016-12-12T08:36:48

#RHS=1+(2cosx(1+cosx))/sin^2x#

#=1+(2cosx(1+cosx))/(1-cos^2x)#

#=1+(2cosx(1+cosx))/((1-cosx)(1+cosx))#

#=1+(2cosxcancel((1+cosx)))/((1-cosx)cancel((1+cosx)))#

#=1+(2cosx)/(1-cosx)#

#=(1-cosx+2cosx)/(1-cosx)#

#=(1+ucosx)/(1-cosx)=LHS#

Proved