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Question #739a4

1 Answer

Dec 11, 2016

#-1/2sin(2x) +C#

Explanation:

#int (1-cot^2x)/csc^2x dx = int (1-(cos^2x/sin^2x))/(1/sin^2x) dx#

# = int (sin^2x-cos^2x) dx#

# = int -cos(2x) dx#

Substitute #u = cos(2x)# to get

# = -1/2 sin(2x) +C#

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